A number consist of two digits whose sum is 8 . If 18 is added to the number its digit are reversed .find the mumber (what is the equation)
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Hey there !!
Let the ten's digit of the original number be x .
And, the unit's digit of the original number be y.
Now, A/Q
⇒ x + y = 8 ............(1) .
The original number = 10x + y .
Number obtained on reversing the digits = 10y + x .
Now,
⇒ 10y + x = 10x + y + 18 .
⇒ 10x - x + y - 10y = -18.
⇒ 9x - 9y = -18.
⇒ 9( x - y ) = -18.
⇒ x -y = -18/9 .
⇒ x - y = -2...........(2) .
On substracting equation (1) and (2), we get
x + y = 8.
x - y = -2.
- + +
_________
⇒ 2y = 10.
⇒ y = 10/2.
∴ y = 5 .
On putting the value of y in equation (1), we get
⇒ x + y = 8.
⇒ x + 5 = 8.
⇒ x = 8 - 5 .
∴ x = 3 .
∵ Original number = 10x + y .
= 10 × 3 + 5 .
= 30 + 5 .
= 35 .
Hence, the original number is 35 .
THANKS
#BeBrainly.
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