Question

A number consist of two digits whose sum is 9 if 27 is subtracted from the number its digit are reversed? find the number​

Answer 1

Answer:

63

Step-by-step explanation:

Let, x be the unit place

      y be the tens place

so, no. becomes= 10y + x

According to question, x+y = 9.....(1)

Also,

10y+x-27=10x+y

10y-y+x-10x=27

9y-9x=27

9(y-x)=27

y-x=3 ....(2)

On adding (1) and (2),

x+y+y-x=9+3

2y=12

y=6

putting this value on eqn (1)

x+6=9

x=3

So, number is 10y +x= 10(6) +3 = 60+3 = 63

I hope it helps u :)