A number consist of two digits whose sum is 9. If 27 is added to the number, the digit are reversed. Find the number
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It is 36 whose sum is 9 and when 27 is added it becomes 63 which is reverse of 36
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Siddhartharao77 Genius
Let the two numbers be a,b.
So, The two digit number will be 10a + b, and reverse of that number = 10b + a
Given, a + b =9 ------------------- (i)
10a + b - 27 = 10b + a
a - b = 3 -------------------- (ii)
On solving (i) and (ii), we get
a = 6
Submit this value in (ii) on we get,
b = 9 - 6 = 3
On submitting the value in above equation we get,
10a + b
= 10 * 6 + 3
=63
So, The number is 63.
Hope this helps!
Read more on Brainly.in - https://brainly.in/question/1465641#readmore
Click to let others know, how helpful is it
5.0
2 votes
THANKS
2
Report
Siddhartharao77 Genius
Let the two numbers be a,b.
So, The two digit number will be 10a + b, and reverse of that number = 10b + a
Given, a + b =9 ------------------- (i)
10a + b - 27 = 10b + a
a - b = 3 -------------------- (ii)
On solving (i) and (ii), we get
a = 6
Submit this value in (ii) on we get,
b = 9 - 6 = 3
On submitting the value in above equation we get,
10a + b
= 10 * 6 + 3
=63
So, The number is 63.
Hope this helps!
Read more on Brainly.in - https://brainly.in/question/1465641#readmore
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