A number consist of two digits whose sum is 9 if 27 is added to the number the digits are reversed find the number
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The 2digit no. is 36
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hi
let the number be xy
tens place =10x
ones place = y
now sum is 9
y + x =9
x = 9 -y
if 27 is added to the number the digits are reversed
10x + y +27 = 10y +x
10x +y - 10y -y = - 27
9x - 9y = 27
x - y = -3
since
x +y = 9
and
x - y = -3
adding both
2x = 6
x = 3
now x +y = 9
3 +y = 9
y = 6
so the number is 36
hope it helps u
;)
let the number be xy
tens place =10x
ones place = y
now sum is 9
y + x =9
x = 9 -y
if 27 is added to the number the digits are reversed
10x + y +27 = 10y +x
10x +y - 10y -y = - 27
9x - 9y = 27
x - y = -3
since
x +y = 9
and
x - y = -3
adding both
2x = 6
x = 3
now x +y = 9
3 +y = 9
y = 6
so the number is 36
hope it helps u
;)
Anonymous:
Nice and bro
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