A number consist of two digits whose sum is 9.if 27is subtracted from the number, its digits are reversed. Find the number.
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Let the no be 10x+y such that x is the digit at tens place and y is the digit at ones place
According to the given conditions,
x + y = 9.........(i)
10x+y-27=10y+x
= 9x-9y=27
= x-y=3.........(ii)
Solving (i) and (ii) by elimination method,
x+y=9
x-y=3
..........
2x = 12
x = 6
Substituting (x = 6) in equation (i)
x + y = 9
6 + y = 9
Then, y = 3
Therefore number is 10x+y = 10*6+3
=63
hope this helps......plz mark as brainliest.....!
According to the given conditions,
x + y = 9.........(i)
10x+y-27=10y+x
= 9x-9y=27
= x-y=3.........(ii)
Solving (i) and (ii) by elimination method,
x+y=9
x-y=3
..........
2x = 12
x = 6
Substituting (x = 6) in equation (i)
x + y = 9
6 + y = 9
Then, y = 3
Therefore number is 10x+y = 10*6+3
=63
hope this helps......plz mark as brainliest.....!
Answered by
4
Answer:
Let the no be 10x+y such that x is the digit at tens place and y is the digit at ones place
According to the given conditions,
x + y = 9.........(i)
10x+y-27=10y+x
= 9x-9y=27
= x-y=3.........(ii)
Solving (i) and (ii) by elimination method,
x+y=9
x-y=3
..........
2x = 12
x = 6
Substituting (x = 6) in equation (i)
x + y = 9
6 + y = 9
Then, y = 3
Therefore number is 10x+y = 10*6+3
=63
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