Question

A number consist of two digits whose sum is 9. If 9 is subtracted from the number it's digits are interchange. Find the number ​

Answer 1

Answer:

Refer the attachment for the answer

Answer 2

Answer:

$\huge\underline\mathfrak\pink{♡QuEsTiOn♡}$

• A number consist of two digits whose sum is 9. If 9 is subtracted from the number it's digits are interchange. Find the number

$\huge\orange{\mid{\fbox{\tt{ANSWER}}\mid}}$

Let the digits at ones place be 'x'

Then the digits at tens place=9-x ......(sum of two digits is 9)

Therefore,

The number

=10 (9-x)+x

=90-10x+x

=90-9x

Now,

Number obtained by reversing the digits:

10x+9-x=9x+9

It is given if 9 is subtracted from the number.,it's digits are interchanged.

=>90-9x-9=9x+9

=>81-9x=9x+9

=>81-9=9x+9x

=>18x=72

=>x=72/18

=>x=4

Digits at ones place is x=4

tens place=9-x=9-4=5

Thus the number is 54

Step-by-step explanation:

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