Question

a number consist of twodigits whise sum is 11. the number formed by reversing the digits is 9 less than the original number. find the number​

Answer 1

Answer:

65

Step-by-step explanation:

11=9+2

8+3

7+4

6+5

5+6

4+7

3+8

2+9

therefore, the numbers and it's reverse are:

92-29

83-38

74-47

65-56

56-65

47-74

38-83

29-92

In these 65-56 applies the rule of the reverse number is 9 less than original number. Therefore, the number is 65

Answer 2

Let the 2 digit number as(10a+b)

Number obtain by reversing the digit=(10b+a)

Given,

( a+b=11)~equation-1

also,

=(10a+b)-(10b+a)=9

=10a+b-10b-a=9

=9a-9b=9

=9(a-b)=9

=(a-b)=9–9

=a-b=1

=a+b+a-b=11+1

=2a=12

=a=6

Putting the value of a in equation 1, we get

=6+b=11

=b=11–6

=b=5

Original number=10×6+5=60+5=65

So the require number is 65