A number consisting of two digits becomes 5/6 of itself, if it's digits are interchanged. If the difference of the digit is 1. Find the number.
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Answered by
15
Answer:
let digit of one's place be x.
so, digit at tens place = x-1.
the number = 10(x-1)+x = 10x-10+x = 11x-10
after interchanging the digits,
the new number = 10x+(x-1) = 11x-1
according to the question,
11x-10 = (5/6)(11x-1)
5(11x-1) = 6(11x-10)
55x-5 = 66x-60
66x-55x = 60-5
11x = 55
x = 55/11 = 5
so, the original number = 11x-1 = 11×5-1 = 55-1 = 54
please mark me as brainliest.
Answered by
0
Answer:
let digit of one's place be x.
so, digit at tens place = x-1.
the number = 10(x-1)+x = 10x-10+x = 11x-10
after interchanging the digits,
the new number = 10x+(x-1) = 11x-1
according to the question,
11x-10 = (5/6)(11x-1)
5(11x-1) = 6(11x-10)
55x-5 = 66x-60
66x-55x = 60-5
11x = 55
x = 55/11 = 5
so, the original number = 11x-1 = 11×5-1 = 55-1 = 54
please mark me as brainliest.
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