a number consisting of two digits is seven times the sum of its digit when 27 is subtracted from the number the digits are reversed find the number
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let the number be 10x+y
10x+y=7(x+y)
10x+y=7x+7y
y=x/2
10x+y-27=10y+x
9x-27=9y
9x-27=9x/2
18x-54=9x
9x=54
x=6
y=3
the no is 63
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