Question

A number consists of 2 digits in which the tenth place digit exceeds the units digit by 7, the number reduces by 63 if the digits are interchanged. Find the number

Answer 1

Step-by-step explanation:

Correct option is D)

Let the digit in the units place =x

Let the digit in the tens place =x+4

∴ The number is 10(x+4)+x=10x+40+x=11x+40

Sum of the digits =x+x+4=2x+4

Given, 2x+4=

7

1

(11x+40)

⇒14x+28=11x+40

⇒3x=12

⇒x=4

∴ the number is 11×4+40=44+40=84.