Question

A number consists of 2-digits of which tens digit exceeds the unit digit by 7. the no. itself is equal to 10 times the sum of digits. find the no

Answer 1

Hello,
let uniti digit be x,
tens  digit = x+7
then value no:
10(x+7)+x;
10x+70+x;
11x+70;
ten times sum of digits
10(x+x+7);
10(2x+7);
20x+70;
according to question 
20x+70=11x+70;
20x-11x=70-70;
9x=0,
x=0
therefore unit digit = 0
tens digit=0+7
therefore no. =70

bye :-)

Answer 2

hello here is your answer
hope it's help you