Question

A number consists of 2 digits of which tens digit exceeds the unit digit by 6 .The number itself is equal to ten times the sum of its digits.Find the number ? ( PLS DEAR EXPERTS ANS URGENTLY)

Answer 1

Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,
y=x+6 -------------(1) and
10y+x=10(x+y)
or, 10y+x=10x+10y
or, x-10x=0
or, x=0
 ∴, y=0+6
or, y=6
∴, the given number is 
10×6+0=60

Answer 2

Hello,

let uniti digit be x,

tens  digit = x+6

then value no:

10(x+6)+x;

10x+60+x;

11x+60;

ten times sum of digits

10(x+x+6);

10(2x+6);

20x+60;

according to question 

20x+60=11x+60;

20x-11x=60-60;

9x=0,

x=0

therefore unit digit = 0

tens digit=0+6

therefore no. =60

bye :-)

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