a number consists of 2 digits of which the tens digit exceeds the units digit by 7.The number itself is equal to ten times the sum of its digits . Find the number.
Answers
Answered by
35
Let the no. be 10x+y.
Then,
Ten's digit = x.
Unit's digit = y.
According to Question,
⇒x-7=y
⇒x-y=7 ...(i)
And also,
⇒10x+y=10*(x+y)
⇒10x+y=10x+10y
⇒10x-10x=10y-y
⇒9y=0
⇒y=0
Putting value of y in equation (i),
⇒x-y=7
⇒x-0=7
⇒x=7
Therefore,
x=7 and y=0,
and the 2-digit number is 10x+y = 10*7 + 0 = 70. Ans.
HOPING THAT IT WILL HELP YOU!!!
Then,
Ten's digit = x.
Unit's digit = y.
According to Question,
⇒x-7=y
⇒x-y=7 ...(i)
And also,
⇒10x+y=10*(x+y)
⇒10x+y=10x+10y
⇒10x-10x=10y-y
⇒9y=0
⇒y=0
Putting value of y in equation (i),
⇒x-y=7
⇒x-0=7
⇒x=7
Therefore,
x=7 and y=0,
and the 2-digit number is 10x+y = 10*7 + 0 = 70. Ans.
HOPING THAT IT WILL HELP YOU!!!
kooper:
plz mark it as the brainliest...
It's wrong the answer is 60
the answer will be 70 because x-y is 7 and not 6
check again that it is written that difference between those digit is 7 not 6
Answered by
2
hey mate here is your answer
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******************************* 70
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