A number consists of 2 digits, the difference of whose digits is 3. If 4 times the number is equal to 7 times the number obtained by reversing the digits, find the number
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63
Step-by-step explanation
suppose the tens digit is a and ones is b
then the two digit number is 10a+b
according to question ,a~b=3(a difference b)..............eq.1
and 4(10a+b)=7(10b+a)
⇒40a+4b=70b+7a
⇒33a=66b
⇒a=2b ...............eq.2
from eq1
if a>b then 2b-b=3
⇒b=3
if b>a then b-2b=3
⇒-b=3
⇒b=-3 { which is not applicable}
so a =2*3=6 [eq 2]
therefore the number =10*6+3=63
hope it will help u mark as brainliest
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