Question

a number consists of 2 digits. The digit in the unit place is 8. If we reverse the digits, the number so formed is seven-fourth the old number. Find the digit in the tens place..​

Answer 1

Step-by-step explanation:

let the no be x and 8

old digit = 10x+8

new digit = 80 + x

according to question..

7/4(10x+8) = 80+x

after solving x = 4

:. at tens place no is 4..

Answer 2

4 will be the digit at tens place.

Step-by-step explanation:

Given that,

The number consists of two-digits

The number at unit place = 8

Now,

Let the number at tens place be x

so,

The old number = 10x + 8

After reversing the number,

The new number = 7/4th of (10x + 8)

A.T.Q.

7/4 of (10x + 8) = 80 + x

⇒ 70x + 56 = 320 + 4x

⇒ 70x - 4x = 320 - 56

⇒ 66x = 264

⇒ x = 264 ÷ 66

∵ x = 4

Thus, the number at tens place would be 4 and the number would be 48.

Learn more: Find the number

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