Question

a number consists of 2 digits the sum of the digit is 12.if 36 is subtracted from the number the digits change their places find the number.

Answer 1

Let xy be the two digit number.

Let x be the digit in ten's place.

Let y be the digit in one's place.

Therefore the two digit number would be 10x+y.   ----- (*)

Given that sum of two digit number = 12.

x + y = 12 ------ (1).

Given that if 36 is subtracted from the number the digits change their places.

10x + y - 36 = 10y + x

9x - 9y = -36

x - y = -4  ------ (2)

On solving (1) and (2), we get

x + y = 12

x - y = -4
--------------

2x = 8

x = 4

Substitute x = 4 in (1), we get

4 + y = 12

y = 12 - 4

y = 8.

Substitute x & y values in (*), we get  10x + y = 10(4) + 8

                                                                           = 48.


Therefore the number is 48.


Hope this helps!

Answer 2

Answer:

Let xy be the two digit number.

Let x be the digit in ten's place.

Let y be the digit in one's place.

Therefore the two digit number would be 10x+y.   ----- (*)

Given that sum of two digit number = 12.

x + y = 12 ------ (1).

Given that if 36 is subtracted from the number the digits change their places.

10x + y - 36 = 10y + x

9x - 9y = -36

x - y = -4  ------ (2)

On solving (1) and (2), we get

x + y = 12

x - y = -4

--------------

2x = 8

x = 4

Substitute x = 4 in (1), we get

4 + y = 12

y = 12 - 4

y = 8.

Substitute x & y values in (*), we get  10x + y = 10(4) + 8

                                                                          = 48.

Therefore the number is 48.

Hope this helps!

Step-by-step explanation: