Question

A number consists of 2-digits. The sum of the digits is 12. If 36 is subtracted from
digits are reversed. Find the nu
the number, the digits change their places. Find the number.​

Answer 1

Answer:

Let xy be the two digit number.

Let x be the digit in ten's place.

Let y be the digit in one's place.

Therefore the two digit number would be 10x+y.   ----- (*)

Given that sum of two digit number = 12.

x + y = 12 ------ (1).

Given that if 36 is subtracted from the number the digits change their places.

10x + y - 36 = 10y + x

9x - 9y = -36

x - y = -4  ------ (2)

On solving (1) and (2), we get

x + y = 12

x - y = -4

--------------

2x = 8

x = 4

Substitute x = 4 in (1), we get

4 + y = 12

y = 12 - 4

y = 8.

Substitute x & y values in (*), we get  10x + y = 10(4) + 8

                                                                          = 48.

Therefore the number is 48.

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