A number consists of 2 digits whose sum is 8. If 18 is added to the number, its digits are interchanged. Find the number
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let x be in tenths place and y be in units place
x+y=8...1
the desired no is 10x+y
18 is added to the no,its digits are interchanged
10x+y+18=10y+x......2
9x-9y=-18
x-y=-2
x+y=8 or,
x=8-y
putting the value of x in eqn ....2
(8-y)-y=-2
y=5
x=8-5
x=3
the desired no is 10x+y
10*3+5=35 is the no.
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