A number consists of 2 digits whose sum is 9. If 27 is substracted from the number its digits are reversed. Find the original number.
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Let us assume the digits be x and y
Then the two-digit number is 10x + y
Given x + y = 9
y = 9 – x ----------------1
Given (10x + y) – 27 = 10y + x
9x – 9y = 27
x – y = 3 ----------------2
Substitute the value of y from eqn 1 in eqn 2
Therefore, x – (9 – x) = 3
2x = 12
x = 6
Therefore, y = 9 – 6 = 3
The two-digit number is 10x + y = (10*6) + 3 = 63
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