A number consists of 2 digits whose sum of the digits is 8. If 8 is added to the number the digits is interchanged their places. Find the number.
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Answer:
Let one of the digit of the two digit number is x.
then problem other number is (8−x)
So,we get the equation
10x+(8−x)+18=10(8−x)+x
10x+8−x+18=80−10x+x
9x+26=80−26
18x=54
x=
18
54
x=3
Then,
The digit in tens place is 3
The digit in ones place is (8−3=5), then the number is 35 and when 18
is added the result is 53 the digits interchange their position in the new number.
Then,
We get the number is 35
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