Question

A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two and the number will be increased by 99 if its digits are reversed. Find the number.

Answer 1

Answer:

352

Explanation:

Let unit digit = x

Let tens digit = x+y

Let hundred digit = y

No. = 100y +10 (x+y) +x

100y + 10x +10y +x

110y +11x

SUM :-

x+(x+y)+y =10

x+x+y+y =10

2(x+y) =10

x+y = 10/2

x+y = 5. ......(1)

So the middle digit is 5.

WHEN REVERSED,

Unit = y

Tens = x+y

Hundred = x

No.= 100x + 10x + 10y + y

110x + 11y

A.T.Q

110x + 11y -110y -11x =99

99x - 99y = 99

99(x - y)=99

x - y = 99/99

x - y = 1. ......(2)

Adding 1 and 2,

x + y + x - y = 5 + 1

2x = 6

x = 3

So., ans is 352

Hope will help u

Answer 2

Answer:

352

Explanation:

IT IS