A number consists of a 2 digit the digit at the tens place is twice that of the digit at unit place if 18 is subtracted. From the number the digits are reversed find the number.
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Answers
Answered by
1
Answer:
21
Step-by-step explanation:
Let the one's place be y and tens digit be x.
then, Number = 10x + y.
∴ Given, (x) = 2y ∴5x=2y⋯(i)
But, if 18 is subtracted, then, number gets reversed
ie. 10y + x.
∴(10x+y)−18=10y+x
⇒10x+y−18=10y+x
⇒10x−x+y−10y−18=0
⇒9x−9y−18=0
⇒x−y−2=0 Putting (y= 5x/2)
x− 5x/2-2=0
2x-x-2=0
X=2
y=1
Answered by
0
Answer:
Let the one's place be y and tens digit be x.
then, Number = 10x + y.
∴ Given, (x) = 2y ∴5x=2y⋯(i)
But, if 18 is subtracted, then, number gets reversed
ie. 10y + x.
∴(10x+y)−18=10y+x
⇒10x+y−18=10y+x
⇒10x−x+y−10y−18=0
⇒9x−9y−18=0
⇒x−y−2=0 Putting [y=
2
5x
]
⇒x−
2
5x
−2=0
⇒2x−x−2=0 ∴y=
2
x
y = 1
⇒x=2
∴ Number = 21
Step-by-step explanation:
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