A number consists of a two digit whose sum is 12. If 8 is added to the number,the digits are reversed.Fimd the number
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sum of two digits is 8 so take digit as A and Bso, A + B = 8........[1]and for original no. 10A + B.....[2]add 18 in this so, 10A + B + 18 the num. is reversed so 10B + A10A + B + 18 = 10B + A9A - 9B = -18A - B = -2......[3]from 3 A = -2 +Bput this in 1 and -2 + B + B = 8so B = 5and form that A = 3so no is 10[3] + 5 = 35 form eq. 2 the no is 35 but after adding 18 => 35 + 18 = 53
Regards;
RASHMI.
sum of two digits is 8 so take digit as A and Bso, A + B = 8........[1]and for original no. 10A + B.....[2]add 18 in this so, 10A + B + 18 the num. is reversed so 10B + A10A + B + 18 = 10B + A9A - 9B = -18A - B = -2......[3]from 3 A = -2 +Bput this in 1 and -2 + B + B = 8so B = 5and form that A = 3so no is 10[3] + 5 = 35 form eq. 2 the no is 35 but after adding 18 => 35 + 18 = 53
Regards;
RASHMI.
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