a number consists of three digit the right hand being zero is the left hand and the middle digits be interchanged the number is diminished by 180 if the left hand digits behalf and the middle and right hand digits we interchange the number is diminished by 454 find the number
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50a-50b=100---1
50a+9b=454----2
(1)-(2),
-59b=-354
b=6
From(1),
50a=100+300=400
=>50a=400
=>a=8
Therefore,number=100×8+10×6=800+60=860.
50a+9b=454----2
(1)-(2),
-59b=-354
b=6
From(1),
50a=100+300=400
=>50a=400
=>a=8
Therefore,number=100×8+10×6=800+60=860.
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