Question

A number consists of three digits of which the middle one is zero and their sum is 4.if the number formed by interchanging the first and last digits is greater than the number itself by 198,then the difference between the first and last digits is

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

Let the number be x,y,z

Number = 100x+10y+z

We are given that the middle one is 0 i.e. y=0

We are given that  their sum is 4

Thus x+y+z=4 --a

Now we are given interchanging the first and last digits is greater than the number itself by 198,

Interchanged no. = 100z+10y+x

now the difference between original no. and interchanged no. is 198

100z+10y+x- (100x+10y+z) =198

99z -99x =198

99(z-x)=198

z-x= 2

thus z = 2+x

Putting these values in a

x+0+2+x=4

2x+2=4

2x=2

x=1

now z = x+2 =1+2

Thus z =3

So, x=1 , y=0, z= 3

Thus number is 103