A number consists of three digits , the right hand digit being zero . If the left hand and the middle digits be interchanged the number is diminished by 180. If the left hand digit be halved and the middle and roght hand digits be interchanged the number is diminished by 454 . Findthe Number
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let x be in hundred place
y be in tens place
third digit is 0 so dont mind it
original number =100x+10y
as per first condition new number
2nd digit becomes first digit
so new number =100y + 10x + 0
EQUATION 1
100x + 10y-180=100y+10x
simplifying we get 90x - 90y=180
90(x - y)=180
x-y=180/90=2
as per second condition new number
fiest digit gets halfed
100x/2=50x
next 2nd digit becomes 1st and viceversa
so 0+1*y
EQUATION 2
100x + 10y -454=50x + y
simplifying we get 50x + 9y=454
third step = multiply 50 in equation 1
so50(x - y)=50*2
50x-50y=100
next subtract thirs step from equation 2
50x + 9y=454
--------
50x-50y=100
___________
0+ 59y =354
we get 59y=354
so y = 6
putting this value to equation 1 we get x as 8
so original number
100x+10y = 800 + 60=860
y be in tens place
third digit is 0 so dont mind it
original number =100x+10y
as per first condition new number
2nd digit becomes first digit
so new number =100y + 10x + 0
EQUATION 1
100x + 10y-180=100y+10x
simplifying we get 90x - 90y=180
90(x - y)=180
x-y=180/90=2
as per second condition new number
fiest digit gets halfed
100x/2=50x
next 2nd digit becomes 1st and viceversa
so 0+1*y
EQUATION 2
100x + 10y -454=50x + y
simplifying we get 50x + 9y=454
third step = multiply 50 in equation 1
so50(x - y)=50*2
50x-50y=100
next subtract thirs step from equation 2
50x + 9y=454
--------
50x-50y=100
___________
0+ 59y =354
we get 59y=354
so y = 6
putting this value to equation 1 we get x as 8
so original number
100x+10y = 800 + 60=860
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