Question

a number consists of two digit digit and the unit place is three times the digit at the tens place if 36 added to a number the digits are reversed find the number

Answer 1

Let the number be xy

Expanded form=10x+y

Since, units place is 3 times the tens place digit

Hence,y=3x

So 10x+3x=13x

After reversing,

10 ×(3x)+x=30x+x=31x

36 added to original number

Then, 13x+36

Sum= 31x

So,

13x+36=31x

36=31x-13x

36=18x

x=2

y=3x=3 (2)=6

So original number is 26

Hope it helps☺