a number consists of two digit of a b**** the tens digit exceeds the units digit by 6 the number itself is equal to 10 times the sum of its digits find the number
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Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,
y=x+6 -------------(1) and
10y+x=10(x+y)
or, 10y+x=10x+10y
or, x-10x=0
or, x=0
∴, y=0+6
or, y=6
∴, the given number is
10×6+0=60
hope it helps u a lot
y=x+6 -------------(1) and
10y+x=10(x+y)
or, 10y+x=10x+10y
or, x-10x=0
or, x=0
∴, y=0+6
or, y=6
∴, the given number is
10×6+0=60
hope it helps u a lot
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