Question

A number consists of two digit of which ones digit exceeds the ten digit by 1.the number itself is equal to four times the sum of its digit. Find the number

Answer 1

Answer:

The number is 12

Step-by-step explanation:

There are two digits:

One in ones and another in tens place and the number in ones place exceeds by 1.

Therefore:

Tens   Ones

10x         x+1

We read that,

The number is 4 times its sum.

=   10x+x+1 = 4(x+x+1)

=     11x+1 = 8x+4

=     3x = 3

=   x=1

Thus, tens digit is 1 and ones is 1+1=2

Thus the number is 12.

HOPE THIS HELPS YOU...

Answer 2

The number is 12.

Given: A number consists of two digits of which one digit exceeds the ten digit by 1. The number itself is equal to four times the sum of its digit.

To Find: The number.

Solution:

Let the digit in one's place be 'x'

Let the digit in ten's place be 'y'

It is said that one's digit exceeds the ten digit by 1.

So, y - x = 1

⇒  y = x + 1                                                                                ......(1)

We can frame the number as = 10x + y = 10x + x + 1

                                                = 11x + 1                                    .......(2)

The sum of the digits = x + y = x + x + 1 = 2x + 1                     ........(3)

According to the conditions given,

         4 × ( 2x + 1 ) = ( 11x + 1 )

    ⇒  8x + 4 = 11x + 1

    ⇒  3x = 3

    ⇒  x = 1

So, y = x + 1 = 1 + 1

        = 2

So, the number should be = 11x + 1 = 11 × 1 + 1

                                            = 12

Hence, the number is 12.

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