A number consists of two digit of which ten's digit exceeds the unit digit by 6. The number itself is equal to ten times the sum of its digit. Find the number
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15
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Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,
y=x+6
10y+x=10(x+y)
10y+x=10x+10y
x−10x=0⇒x=0
y=0+6⇒y=6
the given number is
10×6+0=60
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6
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your answer is and thanks for free point
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