A number consists of two digit of which tens digit exceeds the units digit by 7. The number itself is equal to 10 times the sum of that its digit find the number
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let the required no. be xy=10x+y
x=y+7 (given)
Now,according to question
10(y+7)+y=10(2y+7)
10y+70+y=20y+70
11y=20y
0=9y
0=y
And=y+7=0+7=7
So, the answer should be 70.
x=y+7 (given)
Now,according to question
10(y+7)+y=10(2y+7)
10y+70+y=20y+70
11y=20y
0=9y
0=y
And=y+7=0+7=7
So, the answer should be 70.
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