Question

a number consists of two digit of which tens digit exceeds the unit digit by 6 the number itself is equal to 10 times the sum of its digits find the numbers

Answer 1

let the number be xy where x is in ten's place and y in unit's place .So it can also be expressed as 10(x)+y =10x+y . it is given that x-y =6 => x=6+y . It is given that number itself is 10 time the sum of its digits => 10x+y = 10(x+y) => 10x-10x=10y-y => y =0 . x=6+0=6. So the number is 6(10)+0=60. Hope it helps you...