Question

A number consists of two digit of which tenths digit exceeds the unit digit by 6 the number itself is equal to 10 times the sum of its digit find the number

Answer 1

Let tens digit be x
and unit digit be y
Original Number = 10x +y
According to the question
x =6 +y .....(i)
10x +y = 10(x+y)
10x + y = 10x +10y
10x -10x = 10y-y
9y = 0
y = 0
Put the value of y in equation (i) we get
x = 6+0=6
Original Number = 10(6)+0=60