A number consists of two digit, the sum of which is 5. If the unit's digit is multiplied by 9/2 it will be equal to 3 times the ten's digit number. Find the number.
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Let us assume that, the number is (10x + y).
given that,
Sum of the digits = 5
x + y = 5 -- equation (1)
If unit's digit is multiplied by 9/2 it will be equal to 3 times the ten's digit.
Hence , y*9/2 = 3x
=> y = 3x * 2/9
=> y = 2x/3 -- equation (1)
Substitute "y" value in equation (1)
x + 2x/3 = 5
(3x + 2x)/3 = 5
x = 3*5
x = 15/5
x = 3
Substitute "x" value in equation (2)
y = 2(3)/3
y = 6/3
y = 2
Number = 10x + y
=> 10(3) + 2
=> 32.
Therefore, the two digit number is 32.
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