Question

a number consists of two digit when it is divided by the sum of the digits, the quotient is 6 and remainder is 3.If the digits are interchanged the quotient is 4 and remainder is 9​

Answer 1

Answer:

75

Step-by-step explanation:

let the two digit number be 10x+y and no. obtained by interchanging the digital = 10y+x

As per the first condition

10x+y= 6 (x+y)+3

4x-5y=3.. (i)

As per the second condition

10y+x=4 (x+y)+9

-3x+6y=9.... (ii)

Multiplying equation (i) by 3 and (ii) by 4 and adding them, we get

12x-15y=9

-12x+24y=36

___________

9y=45

y=455

Substitute y=5 in equation (i)

4x- 5X5=36

4x=28

x=7

So the numbers are 10x+y=10×7+5=75

HOPE THIS HELPS YOU!!

HAVE A NICE DAY!!

Answer 2

Answer:

75

Step-by-step explanation:

Let the two digit number be 10x+y and number obtained by interchanging the digit = 10y+x

As per the first condition,

10x+y=6(x+y)+3

4x−5y=3...(i)

As per the second condition,

10y+x=4(x+y)+9

−3x+6y=9...(ii)

Multiplying equation (i) by 3 and (ii) by 4 and adding them, we get

12x−15y=9

−12x+24y=36

9y=45

y=5

Substitute y=5 in equation (i)

4x−5×5=3

4x=28

x=7

So, the number =10x+y=10×7+5=75

I hope it helps you :)