Question

A number consists of two-digit whose sum is 6. If 18 is added to the number, its digit is revered. Find the number.
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Answer 1

Answer:

Let x and y be respectively unit and tenth digit of two-digit number then the number will

10y+x

condition 1:the sum of digits is 6 hence

x+y=6........(i)

condition 2 :when 18 is added to number 10y +x then digits are reversed

i.e

18+10y+x=10x+y

x−y=2...........(ii)

adding (i)and (ii) we get

x=4

by putting value of x in (i) or (ii) we get

y=2

1is added to the number, its digits are reversed. Find the number.}$$

Hence the number is

10y+x

=10×2+4

=24

Hence option A is correct.