Question

a number consists of two digit whose sum is 9 .if 27 is subtracted from the number ,the digit interchange their place .find the number

Answer 1

⭐⭐Hello friend..Ur answer is here⤵⤵

⚫ Let the digits are x and y

then the number will be 10x+y

According to question..

➡x+y=9....equation 1

➡10x+y-27=10y+x

➡9x-9y=27

➡x-y=3....equation 2

Solving equation 1 and 2 we get

➡x=6 and y=3

10x+y=10×6+3=63

➡So the number is 63

I HOPE IT IS HELPFUL TO YOU ☺

Answer 2

Hey friend..!! here's your answer
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Let the unit digit = x
tens digit = y

x + y = 9 ---------------1

According to question ,

10x + y - 27 = 10y + x
9x - 27 = 9y
9x - 9y = 27
x - y = 3 ------------2

By using Substitution Method of equation 1 and 2 ,

x = 9 - y -------------3

From equation 2 and 3

9 - y - y = 3
-2y = -6
y = 3

Put the value of y in equation 3

x = 9 - 3
x = 6

we know that x is unit digit and y is ten's digit.

So the number obtained is 63.


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#hope its help you dear#
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