A number consists of two digits and sum of boths digits is 12. the digits at ones place is three times the digits at tens place. find the number.
Answers
Answered by
50
✯ The number = 39✯
Step-by-step explanation:
Given:
- A number consists of two digits and sum of both digits is 12.
- The digit at one's place is 3 times the digit at ten's place.
To find:
- The number.
Solution:
Let the ten's digit of the number be x and the unit's digit of the number be y.
Then,
- The number = 10x+y
✯
- A number consists of two digits and sum of both digits is 12.
x + y = 12............(i)
✯
- The digit at one's place is 3 times the digit at ten's place.
y = 3x..............(ii)
†Now take eq(i) and put the value of y from eq(ii).
x +3x = 12
4x = 12
x = 12/4
x = 3
†Now put x = 3 in eq(ii) for getting the value of y.
y=3×3
y=9
Therefore,
- The number = 10×3 +9 = 39
__________________
Answered by
132
Given:
- The sum of the digits of a two digits number is 12
- Digit at once place is three times the digit at tens plce.
Find:
- Actual number
Solution:
Let, the ten's digit of the number be x
and the unit's digit be y
So, the Actual number ➨ 10x + y
Now,
Taking eq(2)
Now, put this value of x in eq(1)
So, y = 9
________________
Put value of y in the eq(2)
So, x = 3
________________
Actual Number:
Hence, the actual number will be 39
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