A number consists of two digits in which the tens digit exceeds the units digit by 6. The
number itself is equal to ten times the sum of digits. Find the number.
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Explanation:
Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,
y=x+6
10y+x=10(x+y)
10y+x=10x+10y
x−10x=0⇒x=0
y=0+6⇒y=6
the given number is
10×6+0=60
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