Question

A number consists of two digits in which the tens digit exceeds the units digit by 6. The

number itself is equal to ten times the sum of digits. Find the number.​

Answer 1

Answer:

Step-by-step explanation:

Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,

y=x+6

10y+x=10(x+y)

10y+x=10x+10y

x−10x=0⇒x=0

y=0+6⇒y=6

the given number is  

10×6+0=60

Answer 2

Step-by-step explanation:

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Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,

y=x+6

10y+x=10(x+y)

10y+x=10x+10y

x−10x=0⇒x=0

y=0+6⇒y=6

the given number is

10×6+0=60