Question

A number consists of two digits of which ten's
digit exceeds the unit digit by 7. The number
itself is equal to 10 times the sum of its digits.
Find the number.
​

Answer 1

Answer:

Hello,

Let the number is 10y+x where x is the unit digit and y is the ten's digit.

Then by the given question,

y=x+610y+x

=10(x+y)10y+x

=10x+10yx−10x=0

⇒x=0y=0+6

⇒y=6

the given number is 10×6+0=60

Step-by-step explanation:

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