Question

A number consists of two digits of which ten's digit exceeds the unit digit by 7. the number itself is equal to 10 times the sum of its digits. find the number.​

Answer 1

Hello,

let uniti digit be x,

tens  digit = x+7

then value no:

10(x+7)+x;

10x+70+x;

11x+70;

ten times sum of digits

10(x+x+7);

10(2x+7);

20x+70;

according to question  

20x+70=11x+70;

20x-11x=70-70;

9x=0,

x=0

therefore unit digit = 0

tens digit=0+7

therefore no. =70

Bye Bye.