Math, asked by manish35127, 1 year ago

A number consists of two digits of which ten's digit exceeds the unit digits by 7.The number itself is equal to 10 times the sum of its digits.Find the number.

Answers

Answered by maulikdeadpool

Answer:

The number is 70

Step-by-step explanation:

Let the unit digit be x,

Tens digit = x+7

Then value number

= 10(x+7)+x

= 10x + 70 + x

= 11x + 70

ten times sum of digits

= 10(x+x+7)

= 10(2x+7)

= 20x + 70

according to question

= 20x+70=11x+70

= 20x - 11x = 70-70

= 9x=0

= x=0

therefore unit digit = 0

Tens digit = 0+7

Therefore, number = 70

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