Question

a number consists of two digits of which tens digit exceed the unit digit by 3.the number is 7 times the sum of its digits, find tge number​

Answer 1

Answer:

63

Step-by-step explanation:

Let it's digits be a and b so that the number becomes (ab) to write.

So the number = 10a + b

The tens digit = a = b + 3

The number = 7(sum of digits)

=> 10a + b = 7a + 7b

=> 3a - 6b = 0

or a - 2b = 0

but a = b + 3

so b + 3 - 2b = 0 => b = 3

if b = 3, a = 3+3 = 6.

Hence the number becomes 63.

Answer 2

Answer:

63

Step-by-step explanation: