Question

A number consists of two-digits of which tens digit exceeds the units digit by 3. The number is 7 times
the sum of its digits, find the number.
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Answer 1

Answer:

63

Step-by-step explanation:

Assume Number = XY

[ XY Can be rewritten as X*10+Y

For Example : 53 can be written as (5*10)+3 = 53 ]

Given X=Y+3, so X-Y=3 -----(1)

Also Given , (X*10)+Y = 7(X+Y)

Simplify and we get, 3X-6Y=0 -----(2)

solve (1)&(2)

X=6

Y=3

Number = 63