A number consists of two digits such that the digit
in the unit's place is more by 2 than the digit in the
ten's place. Three times the number added to
times the number obtained by reversing the digits
equals 108. Then the number is:
Answers
Answered by
1
Step-by-step explanation:
step 1 :
let digit in tens place=x
digit in units place=x+2
then the number becomes= 10x+(X+2)
=11x+2----------(1)
step 2:
number obtained by reversing the digits:
digit in tens place becomes=X+2
digit in units place becomes=x
then the number obtained by reversing the digits becomes= 10(X+2)+x
= 11x+20----------(2)
step 3:
it is given in the question that
3 times the number added to the number obtained by reversing the digits=108
therefore,
3(11x+2)+(11x+20)=108
33x+6+11x+20=108
44x+26=108
44x=82
I think the question is wrong!!
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