Question

A number consists of two digits, the difference of whose digits is 3. If 4 times the number is equal to 7 times the number obtained by reversing the digits, find the number.

Answer 1

Step-by-step explanation:

let the number be 10x+y

given x-y=3

A.T.Q

4(10x+y)=7(10y+x)

40x+4y=70y+7x

33x=66y

33x-66y=0

x-2y=0

from (i) y=x-3

putting the value we get

x-2(x-3)=0

x-2x+6=0

-x=-6

(x=6)

substituting the values,

x-y=3

6-y=3

(y=3)

hence the number is 10x+y i.e.,

10(6)+3=63 ans.

hope it helps.....

mark it as brailiest

Answer 2

Answer:

63

Step-by-step explanation

suppose the tens digit is a and ones is b

then the two digit number is 10a+b

according to question ,a~b=3(a difference b)..............eq.1

and 4(10a+b)=7(10b+a)

⇒40a+4b=70b+7a

⇒33a=66b

⇒a=2b ...............eq.2

from eq1

if a>b then 2b-b=3

⇒b=3

if b>a then b-2b=3

⇒-b=3

⇒b=-3 { which is not applicable}

so a =2*3=6 [eq 2]

therefore the number =10*6+3=63