Question

A number consists of two digits,the difference of whose digits is 5.If 8 times the number obtained by reversing the digits,find the number.​

Answer 1

Hope this helps you ☺️☺️

Answer 2

ANSWER:-

Given:

A number consists of two digits, the difference of whose digits is 5. If 8 times the number obtained by reversing the digits.

To find:

The number.

Solution:

Let the digits in ones place be R &

Let the digits in tens place be M.

According to the question:

R-M = 5

=) R= 5+ M............(1)

⚫Let the original number= 10R + M

⚫Reversed number= 10M + R

Now,

=) 10R + M= 8(10M + R)

=) 10R+ M = 80M + 8R

=) 10R- 8R= 80M -M

=) 2R = 79M

=) 2(5+M) = 79M [Using eq.(1)]

=) 10+ 2M= 79M

=) 2M -79M= -10

=) -77M= -10

=) M= -10/-77

=) M= 10/77

Putting the value of M in equation (1), we get;

$R = 5 + \frac{10}{77} \\ \\ = > R = \frac{385 + 10}{77} \\ \\ = > R = \frac{395}{77}$

Thus,

⚫The original number is;

$= > 10R + M \\ \\ = > 10( \frac{395}{77} ) + \frac{10}{77} \\ \\ = > \frac{3950}{77} + \frac{10}{77} \\ \\ = > \frac{3960}{77}$

⚫Reversed Number is;

$= > 10M + R \\ \\ = > 10( \frac{10}{77} ) + \frac{395}{77} \\ \\ = > \frac{100}{77} + \frac{395}{77} \\ \\ = > \frac{100 + 395}{77} \\ \\ = > \frac{495}{77}$

Hope it helps ☺️