a number consists of two digits, the difference of whose digits is 3. if 4 times the number is equal to 7 times the number obtained by reversing the digits, find the number.
Answers
Answered by
0
Let the ones place be x
And tens place be 3-x
The number = 10(3-x) +x
= 30 - 10x + x
= 30 - 9x
After reversing the digits,
The number = 10(x) + 3-x
= 10x + 3 - x
= 9x + 3
According to the question,
4(30 - 9x) = 7(9x - 3)
120 - 36x = 63x - 21
120 + 21 = 63x + 36x
141 = 99x
x = 141/99
Hope it helps :)
Please Mark me as the Brainiest!
Similar questions