Question

a number consists of two digits the digit at the one place is three times the digit at the tens place if 36 is added to the number the digits are reversed find the number.​

Answer 1

Answer:

• The number is 26.

Step-by-step explanation:

Given that:

• A number contains two digits.
• The digit at the ones place is three times the digit at the tens place.
• If 36 is added to the number the digits are reversed.

To Find:

• The number

Let us assume:

• Digit at the tens place be x.

Then,

• Digit at the ones place will be 3x.

Original Number:

10(x) + 1(3x)

= 10x + 3x

= 13x

Reversed Number:

10(3x) + 1(x)

= 30x + x

= 31x

According to the question:

13x + 36 = 31x

Transposing variables and constants to LHS and RHS respectively and changing their sign,

⇒ 13x - 31x = -36

Subtracting 31x from 13x,

⇒ -18x = -36

Removing the minuses,

⇒ 18x = 36

Transposing 18 from LHS to RHS and changing its sign,

⇒ x = 36/18

Dividing 36 by 18,

⇒ x = 2

Hence, x = 2

Therefore,

• Digit at tens place = x = 2
• Digit at ones place = 3x = 3 × 2 = 6

And,

• The number is 26.

Verification:

LHS:

13x + 36

= (13 × 2) + 36

= 26 + 36

= 62

RHS:

31x

= (31 × 2)

= 62

∵ LHS = RHS

Hence, Verified.